Depth to pressure conversion. Leroy '68 equation
Mathematical definition
$$\boxed{P\left( {Z,\phi } \right) = 0.102506\left( {1 + 5.28 \times {{10}^{ - 3}}{{\sin }^2}\phi } \right)Z + 2.524 \times {10^{ - 7}}{Z^2}}$$
Notation | Description | Units | Limits | Conversion |
---|---|---|---|---|
$P$ | pressure | $\text{kPa}$ | $P\left[ {{\rm{kPa}}} \right] = P\left[ {{\rm{kgf/c}}{{\rm{m}}^2}} \right] \times 9.80665 \times {10^1}$ | |
$Z$ | depth | $\text{m}$ | ||
$\phi$ | latitude | $\text{deg.}$ | $-90\ < \phi < 90$ |
Octave/Matlab implementation
function P = depth_to_pressure_sea_leroy_68(D,L)
% Inputs
% D: depth \ m
% L: latitude \ degree \ -90 < L < 90
% Outputs
% P: pressure \ kPa
P = 0.102506*(1+(5.28e-3)*sind(L).^2).*D+(2.54e-7)*(D.^2);
P = P.*9.80665e1;
end
Computational examples
References
- Leroy, Claude C; Parthiot, François, "Depth-pressure relationships in the oceans and seas", 1998